Find the area of metal sheet required to make an open tank of length 10m breadth 7.5m and depth 3.8m
Answers
Answer:
Length of the tank = 10 m
Breadth of the tank = 7.5 m
Depth of the tank = 3.8 m
Area of four walls = 2[L+B] x H = 2(10 + 7.5) x 3.8
= 2 x 17.5 x 3.8 = 35 x 3.8 = 133 m2
Area of the floor = L x B = 10 x 7.5 = 75 m
Area of metal sheet required to make the tank =Area of four walls + Area of floor = 133 m2 + 75 m2 = 208 m2
Given:
✰ Length of a open tank = 10 m
✰ Nreadth of a open tank = 7.5 m
✰ Depth of a open tank = 3.8 m
To find:
✠ The area of metal sheet required to make an open tank.
Solution:
❖ Here first we will find the area of base of the tank and then the area of four walls of tank by using required formula in each case. Then, we will add both the area of base and the area of four walls to get the area of metal sheet required to make an open tank.
✭ Area of four walls = 2 ( l + b ) × h ✭
Putting the values, we have:
➤ Area of four walls = 2 ( 10 + 7.5 ) × 3.8
➤ Area of four walls = 2 × 17.5 × 3.8
➤ Area of four walls = 35 × 3.8
➤ Area of four walls = 133 cm²
Now,
✭ Area of base = l × b ✭
Putting the values, we have:
➤ Area of base = 10 × 7.5
➤ Area of base = 75 cm²
✭ Total Surface Area = Area of four walls + Area of base ✭
➤ Total Surface Area = 133 + 75 cm²
➤ Total Surface Area = 208 cm²
∴ The area of metal sheet required to make an open tank = 208 cm²
▬▬▬▬▬▬▬▬▬▬▬▬▬▬