Question

Find the area of metal sheet required to make two closed hollow cones each of height 24cm and stant
height 25cm​

Answer 1

Step-by-step explanation:

703.36 square cm metal sheet is required .

The capacity of the cone is 1230.88 cubic cm .

Step-by-step explanation:

We are required to find the area of the metal sheet required to make a closed hollow cone of height 24 cm and base radius 7 cm.

So, we are supposed to find the total surface area of cone .

Formula of total surface area of cone = \pi r l+\pi r^{2}πrl+πr

2

Where l is the slant height

r is the radius

So, l=\sqrt{r^2+h^2}l=

r

2

+h

2

Since we are given that the height of the cone is 24 cm and radius of cone is 7 cm.

So, l=\sqrt{7^2+24^2}l=

7

2

+24

2

l=25l=25

Now substitute the values in the formula of total surface area .

Total surface area of cone = 3.14 \times 7 \times 25 +3.14 \times 7^{2}3.14×7×25+3.14×7

2

= 703.36 cm^2703.36cm

2

Thus 703.36 square cm metal sheet is required .

Volume of cone =

3

1

πr

2

h

3

1

×3.14×7

2

×24

= 1230.88cm^31230.88cm

3

Hence the capacity of the cone is 1230.88 cubic cm .