Question

Find the area of minor and major sector and segment of sector angle =60 degree and the radius of circle is 10cm

Answer 1

Area of sector = A /360×πr². .......A= theta

Area of sector = 60/360 ×3.14×10×10

= 1/6×314

= 52.33cm²

Area of circle= πr²

= 3.14×10×10

= 314 cm²

Area of minor sector= area of sector = 52.33 cm²

Area of major sector= area of circle- area of minor arc

= 314-52.33

=261.67cm²