Question

Find the area of minor and major segment of a circle with radius 6 cm and angle 60

Answer 1

Answer:

R= 6cm , theta=60

Area of minor sector

22/7x6x6x60/360

=17.42

In triangle mLo=60 OA=OC=6cm

Area of equilateral triangle

Under root 3/4 x 36 ( square root of 6)

1.73/4 x 36 ( under root 3 = 1.73)

=15.57

Area of minor segments

= Area of minor sectors-Area of triangle

=17.42-15.57

=1.85

Step-by-step explanation:

Hope this will help you