Question

Find the area of minor segment of a circle of radius 6 cm when its chord is subtends an angle 60 at its centre

Answer 1

hey friend,

answer:-

r = 6cm angle = 60

• area of minor Segment =
• ${r}^{2} ( \frac{\pi \times 60}{360 } - \frac{ \sin(60) }{60} )$

by using this formula,u can find answer

i hope this is useful for u