Find the area of minor segment of a circle of radius 6 cm when is called substance at an angle of 60° at its centre
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R= 6cm , theta=60
Area of minor sector
22/7x6x6x60/360
=17.42
In triangle mLo=60 OA=OC=6cm
Area of equilateral triangle
Under root 3/4 x 36 ( square root of 6)
1.73/4 x 36 ( under root 3 = 1.73)
=15.57
Area of minor segments
= Area of minor sectors-Area of triangle
=17.42-15.57
=1.85
Hope this will help you
Area of minor sector
22/7x6x6x60/360
=17.42
In triangle mLo=60 OA=OC=6cm
Area of equilateral triangle
Under root 3/4 x 36 ( square root of 6)
1.73/4 x 36 ( under root 3 = 1.73)
=15.57
Area of minor segments
= Area of minor sectors-Area of triangle
=17.42-15.57
=1.85
Hope this will help you
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