find the area of parabola y2=4ax and the circle x2+y2=8ax
Answers
Answer:
MATHS
Asked on October 15, 2019 byAbhay Bhavsar
Two common tangents to the circle x2+y2=2a2 and parabola y2=8ax are
A
x=±(y+2a)
B
y=±(x+2a)
C
x=±(y+a)
D
y=±(x+a)
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VIDEO EXPLANATION

ANSWER
Equation of tangent to y2=8ax is
ty=x+2at2x−ty+2at2=0
It touches the given circle , so distance of centre from the tangent is equal to radius
⇒1+t20−t(0)+2at2=2a⇒1+t22at2=2a⇒2a2t4=a2+a2t
MATHS
Asked on October 15, 2019 byAbhay Bhavsar
Two common tangents to the circle x2+y2=2a2 and parabola y2=8ax are
A
x=±(y+2a)
B
y=±(x+2a)
C
x=±(y+a)
D
y=±(x+a)
Share
Study later
VIDEO EXPLANATION

ANSWER
Equation of tangent to y2=8ax is
ty=x+2at2x−ty+2at2=0
It touches the given circle , so distance of centre from the tangent is equal to radius
⇒1+t20−t(0)+2at2=2a⇒1+t22at2=2a⇒2a2t4=a2+a2t
MATHS
Asked on October 15, 2019 byAbhay Bhavsar
Two common tangents to the circle x2+y2=2a2 and parabola y2=8ax are
A
x=±(y+2a)
B
y=±(x+2a)
C
x=±(y+a)
D
y=±(x+a)
Share
Study later
VIDEO EXPLANATION

ANSWER
Equation of tangent to y2=8ax is
ty=x+2at2x−ty+2at2=0
It touches the given circle , so distance of centre from the tangent is equal to radius
⇒1+t20−t(0)+2at2=2a⇒1+t22at2=2a⇒2a2t4=a2+a2t
MATHS
Asked on October 15, 2019 byAbhay Bhavsar
Two common tangents to the circle x2+y2=2a2 and parabola y2=8ax are
A
x=±(y+2a)
B
y=±(x+2a)
C
x=±(y+a)
D
y=±(x+a)
Share
Study later
VIDEO EXPLANATION

ANSWER
Equation of tangent to y2=8ax is
ty=x+2at2x−ty+2at2=0
It touches the given circle , so distance of centre from the tangent is equal to radius
⇒1+t20−t(0)+2at2=2a⇒1+t22at2=2a⇒2a2t4=a2+a2t
MATHS
Asked on October 15, 2019 byAbhay Bhavsar
Two common tangents to the circle x2+y2=2a2 and parabola y2=8ax are
A
x=±(y+2a)
B
y=±(x+2a)
C
x=±(y+a)
D
y=±(x+a)
Share
Study later
VIDEO EXPLANATION

ANSWER
Equation of tangent to y2=8ax is
ty=x+2at2x−ty+2at2=0
It touches the given circle , so distance of centre from the tangent is equal to radius
⇒1+t20−t(0)+2at2=2a⇒1+t22at2=2a⇒2a2t4=a2+a2t
MATHS
Asked on October 15, 2019 byAbhay Bhavsar
Two common tangents to the circle x2+y2=2a2 and parabola y2=8ax are
A
x=±(y+2a)
B
y=±(x+2a)
C
x=±(y+a)
D
y=±(x+a)
Share
Study later
VIDEO EXPLANATION

ANSWER
Equation of tangent to y2=8ax is
ty=x+2at2x−ty+2at2=0
It touches the given circle , so distance of centre from the tangent is equal to radius
⇒1+t20−t(0)+2at2=2a⇒1+t22at2=2a⇒2a2t4=a2+a2t
print ("100"+"900") is
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