Question

find the area of parallelogram ABCD with DC =5cm, BC = 7cm and one of its diagonal is 8cm​

Answer 1

HEY MATE ,

AREA OF triangle ABC (by heron's formula )

a= AB ,b=BC, c=AC

s=a+b+c÷2

=5+7+8÷2

=20÷2

=10

area of triangle =

$\sqrt{(s - a)(s - b)(s -c) }$

$\sqrt{(10 - 5)(10 - 7)(10 - 8)}$

$\sqrt{5 \times 3 \times 2}$

$\sqrt{30}$

WE KNOW THE DIGONAL OF PARALLELOGRAM DEVIDES INTO TWO CONGRATULATIONS TRIANGLE.

=area of parallegram ABCD=2×ate of triangle ABC

=

$2 \times \sqrt{30}$

=

$2 \sqrt{30} {cm}^{2}$

I hope it helps u ❣❣❣

Answer 2

Answer:

THE ANSWER IS 10√3 cm²

Step-by-step explanation: