Question

find the area of parallelogram.Base-6 cm, Height-2 cm​

Answer 1

Answer:

a=bxh

a=6x2

area is 12cm square

Answer 2

Given : Base of Parallelogram is 6 cm and Height of Parallelogram is 2 cm .

Need To Find : Area of Parallelogram.

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❍ The Formula for Area of Parallelogram is given by :

$\underline {\frak{\dag As \: We\: know \: that \::}}$

⠀⠀⠀⠀⠀$\underline {\boxed {\sf{ Area _ {( Parallelogram )} = b \times h \: sq.units}}}$

⠀⠀⠀⠀⠀Here b is the Base of Parallelogram & h is the Height of Parallelogram in cm .

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad \qquad \qquad :\implies \sf{ Area_{(Parallelogram)}= 6 \times 2 }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Area_{(Parallelogram)} = 12\: cm^{2}}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Area \:of\:Parallelogram \:is\:12\: cm^{2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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