Question

find the area of parallelogram formed by two vectors A=2i+3j+k and B=i-2j+2k as two adjacent sides (I want only this question answer)​

Answer 1

Answer:

area =√107

Explanation:

$area = \sqrt{107 } \\ a \times b = |i \: \: j \: \: k | \\ i( - 4 - 3) - j(4 - 1) + ( - 4 - 3) k \\ - 7i - 3j - 7k \\ \\ area = \sqrt{ab \times bc} \\ \sqrt{ { - 7}^{2} + { (- 3)}^{2} + {( - 7)}^{2} } \\ \sqrt{49 + 9 + 49 } \\ \sqrt{107}$