Question

find the area of parallelogram having diagonals A=3i+j-2k And B=i-3j+k​

Answer 1

Answer:

Let a = 3i + j - 2k, b = i - 3j + 4k

= i(4 - 3) - j(12 + 1) + k(-9 - 1)

= i - 13j - 10k Area

= | vector a * vector b |

=√(1 + 169 + 100)

= √270 sq.