Question

Find the area of parallelogram: height = 4 , base = 7 with method​

Answer 1

Answer:

the question answer is 28

Answer 2

Step-by-step explanation:

Question :-

• Find the area of parallelogram whose height is 4 units and base is 7 units.

To Find :-

• Area of parallelogram.

Solution :-

Given :

• Height = 4 units
• Base = 7 units

By using the formula,

${\sf{\longrightarrow Area\ of\ parallelogram\ =\ b \times h}}$

Where,

• b = base
• h = height

According to the question, by using the formula, we get :

${\sf{\longrightarrow Area\ of\ parallelogram\ =\ b \times h}}$

${\sf{\longrightarrow 7 \times 4}}$

${\sf{\longrightarrow 28\ sq.\ units}}$

$\therefore$ Hence, area of parallelogram is 28 sq. units.

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$