find the area of parallelogram in which ab =14cm ,bc=10cm and ac= 26cm
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The area of parallelogram is 140cm
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See the attachment
In Δ ABC,
Using Heron's Formula,
S = (a + b + c)/2
⇒ S = (10 + 14 +16)/2
⇒ S = 40/2
⇒ S = 20
Area =
∴ Area of the triangles =
⇒ Area of Δ ABC =
⇒ Area = √4800
⇒ Area = 10√48
⇒ Area = 10√(2 × 2 × 2 × 2 × 3)
⇒ Area = 10 × 2 × 2√3
⇒ Area of Δ ABC = 40√3 cm²
∴ Area of Δ ABC = 69.28 cm².
We know,
Area of the Δ ADC = Area of the ΔABC.
[∵ Both the triangles are congruent)
∴ Area of the Parallelogram = 2 × Area of Δ ABC.
⇒ Area of the Parallelogram = 2 × 69.28 cm²
∴ Area of the Parallelogram = 138.56 cm².
Hence, the Area of the Parallelogram is 138.56 cm².
Hope it helps.
Thanks.
In Δ ABC,
Using Heron's Formula,
S = (a + b + c)/2
⇒ S = (10 + 14 +16)/2
⇒ S = 40/2
⇒ S = 20
Area =
∴ Area of the triangles =
⇒ Area of Δ ABC =
⇒ Area = √4800
⇒ Area = 10√48
⇒ Area = 10√(2 × 2 × 2 × 2 × 3)
⇒ Area = 10 × 2 × 2√3
⇒ Area of Δ ABC = 40√3 cm²
∴ Area of Δ ABC = 69.28 cm².
We know,
Area of the Δ ADC = Area of the ΔABC.
[∵ Both the triangles are congruent)
∴ Area of the Parallelogram = 2 × Area of Δ ABC.
⇒ Area of the Parallelogram = 2 × 69.28 cm²
∴ Area of the Parallelogram = 138.56 cm².
Hence, the Area of the Parallelogram is 138.56 cm².
Hope it helps.
Thanks.
Attachments:
Kirttish:
it is wrong, the formula is base×height and here height means altitude not its side
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