Math, asked by kripasindhu60, 1 year ago

find the area of parallelogram in which ab =14cm ,bc=10cm and ac= 26cm

Answers

Answered by ArpitShrivastav
0
The area of parallelogram is 140cm
Answered by chinmay1312
2
See the attachment


In Δ ABC,
Using Heron's Formula,
S = (a + b + c)/2
⇒ S = (10 + 14 +16)/2
⇒ S = 40/2
⇒ S = 20 

Area = 
∴ Area of the triangles = 
⇒ Area of Δ ABC = 
⇒ Area = √4800
⇒ Area = 10√48
⇒ Area = 10√(2 × 2 × 2 × 2 × 3)
⇒ Area = 10 × 2 × 2√3
⇒ Area of Δ ABC = 40√3 cm²
∴ Area of Δ ABC = 69.28 cm².

We know,
Area of the Δ ADC = Area of the ΔABC.
[∵ Both the triangles are congruent)

∴ Area of the Parallelogram = 2 × Area of Δ ABC.
⇒ Area of the Parallelogram = 2 × 69.28 cm²
∴ Area of the Parallelogram = 138.56 cm².


Hence, the Area of the Parallelogram is 138.56 cm².

Hope it helps.
Thanks.
Attachments:

Kirttish: it is wrong, the formula is base×height and here height means altitude not its side
chinmay1312: who said? it's correct...
chinmay1312: correction done... read the whole question now..
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