Question

Find the area of parallelogram OABC
formed by O(0,0), A(3,5), B(0,5), and C (-3,0)

Answer 1

Answer:

30 units square

Step-by-step explanation:

Answer 2

Answer:

The area of the given parallelogram = 15 square units

Step-by-step explanation:

Area of parallelogram = $\frac{1}{2} \times d_{1} \times d_{2}$

Here, $d_{1}$ = $diagonal_{1}$

$d_{2} = diagonal_{2}$

We can find the area of the given parallelogram by finding the area of two triangles formed inside the parallelogram and then adding them both.

Area of the first triangle = $\frac{1}{2} \times b \times h = \frac{1}{2} \times 3 \times 5 = \frac{15}{2}$

Area of the second triangle = $\frac{1}{2} \times b \times h = \frac{1}{2} \times 3 \times 5 = \frac{15}{2}$

Adding them both = $\frac{15}{2} +\frac{15}{2}= \frac{30}{2} = 15$

Area of the parallelogram = 15 square units

Final Answer:

Hence, the area of the given parallelogram = 15 square units

Link:

https://brainly.in/question/23570882?referrer=searchResults

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