Question

find the area of parallelogram PQRS if PR = 24 cm QU = ST= 6 cm

Answer 1

Solution :-
area of parallelogram = area of trianglePQR+area of trianglePSR
= 1/2×PR×ST + 1/2×PR×QU
= 1/2×24×6 + 1/2×24×6
=72 + 72
=144 sq cm.
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Answer 2

In Δ PSR 
Base =24 cm ( PR )
Height = 6 cm ( ST )
area of Δ = 1 / 2 x  b x h
                = 1/2 x 24 x 6
                 = 72 cm²
in Δ PQR
area = 72
total area = area of PSR + PQR
                = 72 + 72
                = 144 cm²