Find the area of parallelogram whose altitude is 12 cm and base is 6 cm
Answers
Answer:
we will prove that of all the straight lines that can be drawn to a straight line from a given point outside it, the perpendicular is the shortest.
Given: XY is a straight line and O is a point outside it. OP is perpendicular to XY and OZ is an oblique.
Perpendicular is the Shortest
0Save
To Prove: OP < OZ.
Proof:
Statement
Reason
1. In ∆OPZ, ∠OPZ = 90°.
1. OP ⊥ XY.
2. ∠OZP is an acute angle.
2. In a triangle, if one angle is a right angle, the other two must be acute.
3. ∠OZP < ∠OPZ.
3. From statement 1 and 2.
4. OP < OZ. (proved)
4. In a triangle, the greater angle has the greater side opposite to it.
Answer:
72 sq cm
Step-by-step explanation:
=> Area of parallelogram = base × altitude
=> A = b × h
=> A = 12 × 6
=> A = 72 sq cm