find the area of parallelogram whose diagonal are 2ì and 3j
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Answer:
Explanation:
-
3 sq.units
Let vect.a and vect.b be two diagonals of parallelogram.
vect.a = 2i
vect.b = 3j
Area of the parallelogram is calculated by -
A = 1/2 |vect.a × vect.b|
A = 1/2 |2i × 3j|
A = 1/2 |6k|
A = 1/2 × 6
A = 3 sq.units
Area of the parallelogram is 3 sq.units.
Hope it helpz you...
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