Question

find the area of parallelogram whose diagonal are determined by the vector a=3i-j-2k,b​

Answer 1

Answer:

Here a=3i+j−2k,b=i−3j+4k

Thus a×b=

∣

∣

∣

∣

∣

∣

∣

∣

i

3

1

j

1

−3

k

−2

4

∣

∣

∣

∣

∣

∣

∣

∣

=−2i−14j−10k=−2(i+7j+5k)

Hence area of parallelogram =

2

1

∣a×b∣=5

3

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