Math, asked by GothaalaSheoran5821, 10 months ago

Find the area of parallelogram whose one diagonal is 6.8 cm and the perpendicular distance from the opposite vertex.

Answers

Answered by ushakarnath8
5

Answer:

Find the area of a parallelogram, whose one diagonal is 6.8 cm and the perpendicular distance of this diagonal from an opposite vertex is 7.5 cm. The diagnol of a parallelogram divides it into two congruent triangles. So their areas must be equal. So, area of a triangle is 1/2*base*height =1/2*6.8*7.5 = 25.5cm sq.

Answered by abhinav32105
4

answer:

length of its diagonal = 6.8cm

length of perpendicular distance =7.5cm

area of ADC=1/2*base*height

=1/2*6.8*7.5cm^2

since,diagonal divide the parallelogram in two equal area of triangle

then, Area of parallelogram ABCD=1/2*6.8*7.5*2

=6.8*7.5

=51cm^2

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