Find the area of parallelogram whose one diagonal is 6.8 cm and the perpendicular distance from the opposite vertex.
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Find the area of a parallelogram, whose one diagonal is 6.8 cm and the perpendicular distance of this diagonal from an opposite vertex is 7.5 cm. The diagnol of a parallelogram divides it into two congruent triangles. So their areas must be equal. So, area of a triangle is 1/2*base*height =1/2*6.8*7.5 = 25.5cm sq.
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answer:
length of its diagonal = 6.8cm
length of perpendicular distance =7.5cm
area of ∆ADC=1/2*base*height
=1/2*6.8*7.5cm^2
since,diagonal divide the parallelogram in two equal area of triangle
then, Area of parallelogram ABCD=1/2*6.8*7.5*2
=6.8*7.5
=51cm^2
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