Question

Find the Area of parallolelogram where base is 24 meter and height is 12√2 meter

Answer 1

$Let \: b \:and \: h \:are \: base \: and \: height \\of \: a \: parallelogram .$

$Given \: , b = 24 \:m , h = 12\sqrt{2} \: m$

$\boxed { \pink { Area \:of \: the \: parallelogram = bh }}$

$A = 24 \times 12\sqrt{2}\\= 288\sqrt{2} \:m^{2}$

Therefore.,

$\red { Area \:of \: the \: parallelogram}\green { =288\sqrt{2} \:m^{2}}$

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Answer 2

Given:

• Base (b) = 24 m

• Height (h) or Altitude = 12√2

To find out:

Find the area of parallelogram.

Formula used:

Area of parallelogram = Base × Altitude

Solution:

Area of parallelogram = Base × Altitude

✪ Putting the values of base and Altitude

⇒ 24 × 12√2

⇒ 288√2

⇒ 288 × 1.414

⇒ 407.232 m²

⇒ 408 m² (approx)

Knowledge Enhancer:

• Area of trapezium = ½ × ( b1 + b2 ) × h

• Area of triangle = ½ × Base × Height

• Area of equilateral triangle = √3/4 (side)²

• Area of circle = πr²

• Area of Rhombus = ½ × Product of diagonals