find the area of path running outside the following fields of given dimension.20m×15.5m,breadth of the path is 1.5m.
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Answer:
dimension of the inner path
20-(1.5+1.5)
17
(length)
15.5-(1.5-1.5)
12.5
(breadth)
AREA OF OUTER CIRCLE -- AREA OF OUTER CIRCLE.
(20×15.5)=310
outer circles area
(17×12.5)=212.5
inner circle area
(310 - 212.5)
=97.5m square
:The area of the path is 97.5m square.
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