find the area of pentagon PQRST in which QD I PR, RE 1 PS
+ PS such that PR = 10 cm, PS = 12 cm, QD = 3 cm,
RE = 7 cm and TF = 5 cm.
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Answer:87 sq.cm
Step-by-step explanation:In ∆QPR
B =10 cm
H=3cm
Area =1/2×10×5
=15 sq.cm
In ∆RPS
B=12cm
H=7cm
Area=1/2×12×7
=42sq.cm
In ∆TPS
B=12cm
H=5cm
A=1/2×12×5
=30sq.cm
Total Area of the figure = 15+42+30=87sq.cm
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