Question

Find the area of polygon ABCDE whose measurements in meter are give in the following figure?​

Answer 1

Answer:

Here

construct OD , MC , EN perpendicular to AB , BD and AD respectively

In triangle ADO

Angle DOA = 90 degree

then triangle ADO is a right triangle

also , AO = 1/2AB

i.e. AO = 5 cm

By pythagoras theorem in triangle ADO

(AD)2 = (OD)2 + (AO)2

(12) sq. = (OD)2 + (5)sq.

144-25 = (OD)2

sq.root over 119 = (OD)

then ,

ar(triangle ADB) = 1/2×base × height

= 1/2 × 10×sq.root119

= 5sq.root 119 cmsq.

similarly ,

in triangles ADE and BCD

EN and MC are the altitudes of the triangles

By the pythagoras theorem

in triangles EOD and COD

EN= 2root7 cm

MC= 8 cm

ar(polygon ABCDE) = ar(ADB)+ar(ADE)+ar(BCD)

=5root119+1/2× AD × EN + 1/2× BD × MC

= 5root119 + 1/2×12×2root7 + 1/2 × 12 ×8 =5root7×17 + 12root7 + 48

=(5root119 + 12 root7 +48 ) cm sq.

thus the required answer

hope it helps

Answer 2

Answer:In ∆, A,D,E = a+b+c

Step-by-step explanation: