Question

Find the area of polygon in fig.13.24​

Answer 1

Solution

The given polygon can be divided into 3 parts , 2 triangles and a rectangle.

Consider the Rectangle FBCE

• Length of the rectangle (FE) = 50 cm
• Breath of rectangle (FB) = 30 cm

Now,

$\fbox{ \sf{{ \red{area \: of \: rectangle= Length× breath}}}}$

$\sf{ \to \: Area \: of \: rectangle= 50×30} \\ \sf{ \to \: Area \: of \: rectangle= \green{1500 cm²}}$

Now, consider the triangle ∆DCE

• Height= 10 cm
• base = 30 cm

$\boxed{ \sf{ \color{grey}area \: of \: triangle = \frac{1}{2} ×base \: ×height}}$

$\: \: \sf{ \to \: area \: of \: triangle= \frac{1}{2} × 30×15} \\ \sf{ \to \: area \: of \: triangle= \green{ 150 cm²}}$

Similarly the ∆ AFB have same base and height as ∆DCE.

so area of ∆ABF is 150cm²

→area of polygon= (150+150 +1500)cm²

→area of polygon=1800 cm²

So the area of the given polygon is 1800 cm².

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