Find the area of polygon
please solve step by step
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Answer: 4950 m²
Step-by-step explanation:
(Assume that ∠EDC,∠GDA,∠ECF,∠EBH,∠BCF,∠ABH are all right -angled)
Area of ΔDEG = 1/2 * 30 * 20 = 15 * 20 = 300m²
Area of ΔECF = 1/2 * 60 * 50 = 30 * 50 = 1500m²
Area of ΔADG = 1/2 * 100 * 20 = 50 * 20 = 1000m²
For ∠CBH,∠BCF are right-angled , height is CB only .
∴ Area of Trapezium BCFH = 30(50+40)/2 (By the formula of are of a trapezium , and height is BC)
= 30 * 90 / 2 = 30 * 45 = 1350m²
Area of ΔABH = 1/2 * 40 * 40 = 20 * 40 = 800m²
∴ Area of the polygon = (300 + 1500 + 1000 + 1350 + 800)m²
= 4950 m²
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