Question

Find the area of PQRS if PR = 16.5 m, SA=4.2 m, QB = 3.8 m. Also, find
the cost of painting the picture at the rate of 5 per cm².
See the diagram in the picture​

Answer 1

PR = 16.5

SA = 4.2

QB = 3.8

so according to the given diagram in the triangle PSR the PR is perpendicular till the point S so it is the altitude of the triangle

Now, area of PSR

$Area = \frac{1}{2} \times base \times height$

$Area = \frac{1}{2} \times 16.5 \times 4.2$

$Area = 34.65$

similarly in the triangle PQR the area of PQR is

$Area = \frac{1}{2} \times 16.5 \times 3.8$

$Area = 31.35$

now total area

34.65 + 31.35 = 66 cm$^2$

so cost of painting will be

$66 \times 5 = 330 \: rupees$

Answer 2

Answer:

66 m², ₹33,00,000

Step-by-step explanation:

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