Question

find the area of prellelogran whose base is 20cm and height is 13cm​

Answer 1

Answer:

Area of parallelogram=2(area of triangle)

=2(1/2*base*height)

=2(1/2*20*5)

=2(50)

=100 sqm

Answer 2

Given :

• Base of Parallelogram = 20cm

• Height of Parallelogram = 13cm

To Find :

• Area of Parallelogram = ?

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \\ \end{gathered}\end{gathered}\end{gathered}$

Solution

~Formula Used :

${\underline{\boxed{\pmb{\sf{ Area = Base \times Height }}}}}$

Where

• B = Base

• H = Height

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}\end{gathered}\end{gathered}$

~Calculating The Area

$\begin{gathered}\begin{gathered}\begin{gathered} {\longmapsto{\qquad{\sf{ Area = Base \times Height }}}} \\ \\ \\{\longmapsto{\qquad{\sf{ Area = 20\times 13 }}}} \\ \\ \\ {\longmapsto{\qquad{\sf{ Area = 20\times 13 =260 }}}} \\ \\ \\ {\longmapsto{\qquad{\sf{ Area = { \color{lime}{{ \underline{260cm {}^{ {}^{2} } }}}}}}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\color{aqua}{\pmb{\frak{ Area =260\; {cm}^{2} }}}}}}}}\end{gathered}\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\\ \qquad{\rule{150pt}{1pt}} \end{gathered}$

~Therfore

❛❛ Area of the given parallelogram is  260cm² . ❜❜

$\begin{gathered}\begin{gathered}\begin{gathered} \\ {\underline{\rule{180pt}{9pt}}} \end{gathered} \end{gathered}\end{gathered}</p><p>$