Question

find the area of quadrant of a circle whose circumference of a circle exceeds its diameter by 15 cm.

Answer 1

Area of sector is n/360×πr²
So solve in the given below way in attachment

Answer 2

Answer:

The area of quadrant of a circle is 9.62 cm².

Step-by-step explanation:

It is given that circumference of a circle exceeds its diameter by 15 cm.

Circumference of a circle is 2πr.

$2\pi r=d+15$

$2\pi r=2r+15$

$2(3.14) r-2r=15$

$2r(3.14-1)=15$

$2r(2.14)=15$

$r=\frac{15}{4.28}=3.5$

The radius of the circle is 3.5 cm.

The area of quadrant of a circle is

$A=\frac{1}{4}\pi r^2$

$A=\frac{1}{4}\pi (3.5)^2$

$A=9.6211$

$A\approx 9.62$

Therefore the area of quadrant of a circle is 9.62 cm².