Question

find the area of quadrant of circle whose circumference is 22 centimetres

Answer 1

Heya...
Here is your answer ----

Circumference = 22 cm

=>Circumference = 2 × π × r

=> 22 = 2 × 22/7 × r

=> 22 = 44 / 7 r

=> 44r = 22 × 7

=> 44r = 154

=> r = 154/44

=> r = 77/22

=> r = 7/2

Now, area of a quadrant = 1/4 × π × r^2

=> Area of quadrant = 1/4 × 22/7 × (7/2)^2

=> Area of quadrant = 1/4 × 22/7 × 49/4

=> Area of quadrant = 1/4 × 22 × 7/4

=> Area of quadrant = 154/16

=> Area of quadrant = 9.6 cm^2 (approx)

HOPE IT HELPS....!!!!

Answer 2

Generally area of a quadrant = 1/4*π*r²,
and circumference of a quadrant = (πr)/2 + 2r,
Where r is radius,
Assume π = 3.14

Given that circumference of quadrant = 22 cm 
=> πr + 4r = 44 cm,
=> r(π+4) = 44cm
=> r(7.14) = 44
=> r is nearly 6.16 cm, If we can ignore the decimal value r = 6cm,
Remember :  We can find the area of quadrant but we will get an near value,

=> Area = 1/4 * 22/7 * 6 * 6 cm²
=> Area = 28.274 cm² Which is nearly 28 cm² If we ignore the decimal value again,

Here is the answer, It is 28cm² nearly not exactly,

Hope you understand, Have a great day !