Math, asked by gouthamchowdaryc, 2 months ago

find the area of quadrilateral ABCD

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Answered by ITISNISHANT07

2

Answer:

GIVEN

AK = 8CM , BK = 2CM

IN ∆ ABK

ANGLE K = 90°

THEN,

BY PYTHAGORAS THEOREM

HYP² = S1² + S2²

AB² = AK² + BK²

AB² = 8² + 2²

AB² = 64 + 4

AB² = 68

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