Question

Find the area of quadrilateral ABCD

Answer 1

area of quadrilateral=1/2 × diagonal (H1+H2)
area of ABCD=1/2×22(3+3)
= (22×6)/2
=66 cm²

Answer 2

Area of this Quadrilateral = area of 2 triangles

$= 1 \div 2 \times 22 \times 3 + 1 \div 2 \times 22 \times 3$
$= 11 \times 3 \: + \: 11 \times 3$
$= 66 {cm}^{2}$