Question

find the area of quadrilateral abcd as shown in figure given below​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given -

Figure

To Find -

• Area of quadrilateral ABCD

As we know that :-

• Area of right angle triangle is 1/2 × base × height

In the given figure ΔBCD and ΔABD, are right angle triangle

Now,

In ΔBCD,

Area = 1/2 × 9 × 12

» 9 × 6

• » 54 cm²

And

In ΔABD,

By Pythagoras theorem :-

• (AD)² = (AB)² + (BD)²

» (17)² = (AB)² + (15)²

» AB = √289 - 225

» AB = √64

• » AB = 8 cm

Now,

Area of ΔABD =

» 1/2 × 8 × 15

» 4 × 15

• » 60 cm²

Now,

• Area of quadrilateral ABCD = Area of ΔABD + Area of ΔBCD

» 60 + 54

• » 114 cm²

Hence,

The area of quadrilateral ABCD is 114 cm².

Formula Used :-

• Area of triangle = 1/2 × Base × height

Pythagoras theorem :-

• (Hypotenuse)² = (Perpendicular)² + (Base)²