Question

Find the area of quadrilateral ABCD as shown in the figure:​

Answer 1

Answer:

Area of quadrilateral =

$\frac{1}{2} \times d \: (h1 + h2)$

here. d= length of diagonal

h1 and h2 are two heights.

$area = \frac{1}{2} \times 15(3 + 5) \\ \\ = \frac{1}{2} \times 15 \times 15 \\ \\ = \frac{225}{2} \\ \\ = 112.5$

So area of quadrilateral = 112.5cm²

Answer 2

i hope it's helpful