Question

Find The Area Of Quadrilateral ABCD By Determinant Method...​

Answer 1

Answer:

Area of given  quadrilateral = 17.5 Sq.Units

Step-by-step explanation:

Let  x1 = -3     x2 = -2      x3 = 4     x4 = 2     and

     y1 = 1         y2 = -2      y3 = 1      y4 = 3

Area of a quadrilateral

= ( 1 / 2 ) | ( x1.y2 - x2.y1 ) + ( x2.y3 - x3.y2 ) + ( x3.y4 - x4.y3 ) + ( x4.y1 - x1.y4) |

= ( 1 / 2 ) | ( -3.-2   -    -2.1 ) + ( -2.1   -     4.-2 ) + ( 4.3    -     2.1 ) + ( 2.1     -   -3.3) |

= ( 1 / 2 ) | ( 6  -    -2 ) + ( -2   -     -8 ) + ( 12    -   2) + ( 2     -     -9) |

= ( 1 / 2 ) | ( 6  +   2 ) + ( -2   +  8 ) + ( 12    -   2) + ( 2     +   9) |

= ( 1 / 2 ) | ( 8 ) + ( 6 ) + ( 10 ) + ( 11 ) |

= ( 1 / 2 ) | 35 |

=17.5 Sq.Units

Area of given  quadrilateral = 17.5 Sq.Units