Question

find the area of quadrilateral ABCD here AC= 22 CM BM= 3 cm DN =3 cm and BM perpendicular AC and perpendicular AC​

Answer 1

Answer:

area of quadrilateral=d/2×(h'+h")

22/2×(3+3)

=11×6

=66cm²

Answer 2

Answer:

66cm^2 is the answer

Step-by-step explanation:

To find the area of quadrilateral ABCD, first we have to find the area of ΔABC, and ΔADC Area of ΔABC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Area of ΔADC = ½ × Base × Height

= ½ × 22 × 3

= 1 × 11 × 3

= 33 cm2

Then,

Area of quadrilateral ABCD = Area of ΔABC + Area of ΔADC

= 33 + 33

= 66 cm2