Find the area of quadrilateral ABCD
Here,AC=22cm,BM=3cm,DN=3 cm, andBm!AC,DR! AC?
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Step-by-step explanation:
Given: AC = 22 cm, BM = 3 cm, DN = 3 cm
Area of the ∆ ABC = 1/2 × base × height
= 1/2 × AC × BM
= 1/2 × 22 cm × 3 cm
= 33 cm2
Area of the ∆ ADC = 1/2 × base × height
= 1/2 × AC × DN
= 1/2 × 22 × 3
= 33 cm2
Area of the quadrilateral ABCD = Area of the ∆ ABC + Area of the ∆ ADC
= 33 cm2 + 33 cm2
= 66 cm2
☛ Check: NCERT Solutions Class 7 Maths Chapter 11
Video Solution:
Find the area of the quadrilateral ABCD. Here, AC = 22 cm, BM = 3 cm, DN = 3 cm, and BM ⊥ AC, DN ⊥ AC
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