Question

Find the area of quadrilateral ABCD.
Here, AC=22cm, BM=3cm,DN=3cm, and BM is perpendicular to AC, DN is perpendicular to AC​

Answer 1

$Here, AC=22cm, BM=3cm, DN=3cm</p><p>Area of quadrilateral ABCDF=Area of ΔABC+Area of ΔADC</p><p>=21×AC×BM+21×AC×DN</p><p>=21×22×3+21×22×3</p><p>=3×11+3×11</p><p>=33+33</p><p>=66cm2</p><p>Thus, the area of quadrilateral ABCD is cm2.</p><p></p><p>$

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