Question

Find the area of quadrilateral ABCD here AD= 42m, CM= 9m, AN = 12m and AN parallel to BD, CM parallel to BD

Answer 1

The area of the given quadrilateral ABCD is 441 cm².

Step-by-step explanation:

Referring to the given figure, we have

ABCD is a quadrilateral  

BD = 42 cm

AN = 12 cm

CM = 9 cm

AN and CM are perpendicular to BD

Now,

Consider ∆ABD, we have

Base, BD = 42 cm

Height, AN = 12 cm  

∴ Area of ∆ABD = ½ * base * height = ½ * 42 * 12 = 252 cm² ….. (i)

And,

Consider ∆CBD, we have

Base, BD = 42 cm

Height, CM = 9 cm  

∴ Area of ∆CBD = ½ * base * height = ½ * 42 * 9 = 189 cm² …… (ii)

Thus,  

The area of the quadrilateral is given by,

= [Area of ∆ABD] + [Area of ∆CBD]

Substituting from (i) & (ii)

= 252 cm² + 189 cm²

= 441 cm²

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Also View:  

A diagonal of a quadrilateral is 26cm and the perpendicular drawn to it form the opposite vertices are 12.8cm and 11.2 cm.find the area of the quadrilateral.  

https://brainly.in/question/1811788  

The length of the diagonal of the quadrilateral is 24 cm. the length from the perpendicular from the opposite vertices on this diagonal are 8.4cm and 7.6cm . find the area of the quadrilateral. also find the ratio of the areas of the two triangles into which the diagonal divides the quadrilateral.  

https://brainly.in/question/2232120

Answer 2

• Answer is 441m square
• Step-by-step explanation:
• Area of triangle BCD +Area of triangle ABD 1/2×Base×Height +1/2×Base×Height
• 1/2×42×9+1/2×42×12
• 189+252
• 441