Find the area of quadrilateral abcd in which ab=22cm and bm=3cm
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Step-by-step explanation:
Here, AC = 22 cm, BM = 3 cm, DN = 3 cm
Area of quadrilateral ABCDF = Area of Δ ABC + Area of Δ ADC
= 1/2 x AC x BM + 1/2 x AC x DN
= 1/2 x 22 x 3 + 1/2 x 22 x 3 = 3 x 11 + 3 x 11 = 33 + 33 = 66 cm2
Thus, the area of quadrilateral ABCD is 66 cm2.
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