Find the area of quadrilateral ABCD in which AB=8cm ,BC =6cm, CD=8cm ,DA=10cm, and AC=10cm ?
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Answer:
Area of quadrilateral ABCD is the sum of areas of triangles ABC & ADC
Use the formula of area of a triangle with sides a, b and c as Δ=√s(s−a)(s−b)(s−c) where the perimeter is given by 2s=a+b+c . So area of triangle ΔABC=√12(12−8)(12−6)(12−10)=√12∗4∗6∗2=24 square cm & area of ΔADC=√14(14−10)(14−10)(14−8)=8√21∼8∗4.58=36.66 square cm
So, the area of the quadrilateral is 24+36.66=60.66 square cm.
∴ your answer is 60.66
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