Question

Find the area of quadrilateral ABCD in which AB is equal to 3 cm BC is equal to 4 cm CD is equal to 4 cm, DA is equal to to 5 cm and AC is equal to 5 cm

Answer 1

Answer:

Hey as it is a quadrilateral triangle so the area = 3× sum of sides

so now sum of sides = 3+4+4+5+5 = 21

So now Area = 3× 21 = 63 cm2

so area = 63cm2

I'd answer is correct

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Answer 2

Answer:

AC divides the quadrilateral in 2 triangles.

we can find areas of the two triangles by herons formula

A=√s(s-a) (s-b) (s-c)

In ∆ABC, ab=3 bc=4 ac=5

s=p/2=12/2=6

A=√6(6-3) (6-4) (6-5)

= √6(3) (2) (1)

=√2×3×3×2

= 6sq cm

now,

in ∆ADC, AC=5 AD=5 CD= 4

s= 14/2=7

A=√7(7-5) (7-5) (7-4)

=√7(2) (2) (3)

=2√21 sq cm

Adding areas of both triangles..

we get the area of the quadrilateral..

so area of quadrilateral= 6+2√21 sq. cm.