Question

Find the area of quadrilateral ABCD in which AC = 40 m, DP = 8 m, BQ = 10 m​

Answer 1

Answer 360m^2

= ( 1/2×AC×BQ) + ( 1/2×AC× DP)

= 1/2×AC(BQ+DP)

=1/2×40(10+8)

=1/2×40(18)

=1/2×720

=720/2

=360m^2