find the area of quadrilateral ABCD in which ANGLE BCA= 90degree AB=13 cm and ACD is an equilateral triangle of side 12cm
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IN ΔABC
SINCE IT IS A RIGHT ANGLEDΔ ,LET BC BE X
BY PYTHAGORAS THEOREM
(13)²=(X)² +(12 )² ,(X)²=25
X=5,BC = 5
AREA TRIANGLE ABC=1/2×12×5 = 30
IN ΔACD SINCE IT IS AN EQUILATERAL Δ
AREA =√3/4 (SIDE)² =36√3
AREA OF QUADRILATERAL =36√3+30
SINCE IT IS A RIGHT ANGLEDΔ ,LET BC BE X
BY PYTHAGORAS THEOREM
(13)²=(X)² +(12 )² ,(X)²=25
X=5,BC = 5
AREA TRIANGLE ABC=1/2×12×5 = 30
IN ΔACD SINCE IT IS AN EQUILATERAL Δ
AREA =√3/4 (SIDE)² =36√3
AREA OF QUADRILATERAL =36√3+30
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