Question

find the area of quadrilateral ABCD in which ANGLE BCA= 90degree AB=13 cm and ACD is an equilateral triangle of side 12cm

Answer 1

IN ΔABC
SINCE IT IS A RIGHT ANGLEDΔ     ,LET BC BE X
BY PYTHAGORAS THEOREM
(13)²=(X)²  +(12 )² ,(X)²=25
X=5,BC = 5
AREA TRIANGLE ABC=1/2×12×5 = 30
IN ΔACD SINCE IT IS AN EQUILATERAL Δ
AREA =√3/4 (SIDE)²  =36√3
AREA OF QUADRILATERAL =36√3+30

Answer 2

Answer:

Step-by-step explanation:here is ur answer