Question

find the area of quadrilateral ABCD, in which diagonal AC= 6cm altitude BN=3cm and DN=5cm​

Answer 1

Answer:

Given : Length of the diagonal (AC)=10 cm

Area of quadrilateral ABCD=ar(△ABC)+ar(△ACD)

=(

2

1

×AC×BM)+(

2

1

×AC×DL)

=

2

1

×AC(BM+DL)

=

2

1

×10(5+6)

=5×11cm

2

=55cm

2