find the area of quadrilateral ABCD in which diagonal BD equals 24 cm. Al perpendicular to BD and CM perpendicular to BD such that AL equals to 5 cm and CM equals to8 cm
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Step-by-step explanation:
consider triangle ABD
where base =24 cm
altitude =5 cm
ar of triangle ABD = 1/2 bh
=. 60 cm square
consider triangle DBC
base =24 cm
altitude=8cm
area = 1/2 bh
= 96 cm square
sum of area of two triangle = area of quadilateral
96+69 =165 cm square
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