Question

Find the area of quadrilateral ABCD in which diagonal BD = 24 cm. AL ⊥ BD and CM ⊥ BD such that AL = 5 cm and CM = 8 cm.

Question

Answer 1

in triangle ABD

1/2 × base × height

1/2 × 24 × 5

=60

in triangle BCD

1/2 × base × height

1/2 × 24× 8

=96

adding both areas

=60+96

=156