find the area of quadrilateral ABCD in which diagonal Bd = 24cm. AL BD and CM BD such that AL= 5cm and CM = 8cm.
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Answered by
91
in triangle ABD
1/2 × base × height
1/2 × 24 × 5
=60
in triangle BCD
1/2 × base × height
1/2 × 24× 8
=96
adding both areas
=60+96
=156
1/2 × base × height
1/2 × 24 × 5
=60
in triangle BCD
1/2 × base × height
1/2 × 24× 8
=96
adding both areas
=60+96
=156
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Answered by
17
Answer:
in triangle ABD
1/2 × base × height
1/2 × 24 × 5
=60
in triangle BCD
1/2 × base × height
1/2 × 24× 8
=96
adding both areas
=60+96
=156
Step-by-step explanation:
hope you like it its a question from rs agarwal mathematics bookit I am not wrong do mark a s brainliest
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