Question

Find the area of quadrilateral ABCD in which diagonals AC and BD measure 52 m. And 36 m respectively and are perpendicular to each other.

Answer 1

In a quadrilateral if diagnol are perpendicular then the quadrilateral is said to be rhombus.

Area of rhombus= 1/2×product of diagnols

=1/2×52×36

=936sq.m

:-)hope it helps u.

Answer 2

Answer:  Area of quadrilateral ABCD is 936 cm².

Step-by-step explanation:

Since we have given that

ABCD is a quadrilateral in which AC and BD are diagonals that are perpendicular to each other.

AC = 52 m

BD = 36 m

Since it forms a rhombus.

As we know the formula for "Area of rhombus":

$Area=\frac{1}{2}\times AC\times BD\\\\Area=\frac{1}{2}\times 52\times 36\\\\Area=936\ cm^2$

Hence, Area of quadrilateral ABCD is 936 cm².