Question

find the area of quadrilateral ABCD,where AB parallel to CD, AB=9,BC=10,CD=12 and AD=11 cm.​

Answer 1

Answer:

$100 cm^{2}$

Step-by-step explanation:

$Area = \frac{9+11}{2}(10)$

         $= \frac{20}{2} (10)$

         $=10(10)$

         $=100cm^{2}$