Question

find the area of quadrilateral abcd where BD=22cm, CE=7cm and AF=6cm
refer the picture​

Answer 1

Answer:

Area of quadrilateral ABCD= area of triangle BCD+area of triangle ABD

=1/2(BD)(CE)+1/2(BD)(AF)

=1/2×22×7+1/2×22×6

=77+66

=143 sq. Units

Step-by-step explanation:

Answer 2

Answer:

The area of quadrilateral ABCD is 132 square cm.

Step-by-step explanation:

We can use the formula for the area of a trapezoid to find its area. The formula is A = 1/2 × (a + b) × h, where a and b are the lengths of the two parallel sides, and h is the perpendicular distance between them.

In this case, BD is one of the parallel sides, so we can call it a. To find the other parallel side, we need to use the fact that triangles ABD and CDE are similar. This means that their corresponding sides are proportional. In particular, we can write:

AB/CD = BD/CE

Substituting the given values, we get:

AB/CD = 22/7

Cross-multiplying, we get:

AB = (22/7) × CD

Now, we know that AF is the perpendicular distance between the two parallel sides. Therefore, we can call it h. Substituting the given value, we get:

h = 6 cm

Substituting all the values into the formula for the area of a trapezoid, we get:

A = 1/2 × (a + b) × h

A = 1/2 × (BD + (22/7) × CD) × 6

A = 3(BD + (22/7) × CD)

Substituting the given values, we get:

A = 3(22 + (22/7) × 7)

A = 3(22 + 22)

A = 132 square cm

The area of quadrilateral ABCD is 132 square cm.

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